Hay,
I started with co-functions a little while back, I got the concept and understand the A + B = 900,
But i got this one that threw me a curve-ball,
sin (900 + x) = 2 cos2x
I spoke to my lecturer about this one and he said just to treat the second part as a normal square,
Where is what i tried...(Thinking)
sin (900 + x) = 2[sin(900-x)2]
sin (900 + x) = 2[(900-x)(900-x)]
900-x = 2[8100 - 1800x + x2]
900-x = 16200 - 3600x + 2x
2x2 - 3610x + 15300 = 0
Using quadratic formula:
.'. x = 3 + "root 12231" /4 or .'. x = 3 -"root 12231" /4
.'. x = 28.398 or .'. x = -27.145
Did i miss something here or look at it from a wrong angle?