sinA+sinB+sinC=4cos1/2Acos1/2Bcos1/2C ..guys can you help me in proving this one..tnx..
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Yikes this is hard to read, some brackets or spaces would be nice >< Is it ?
Originally Posted by fireboy25 sinA+sinB+sinC=4cos1/2Acos1/2Bcos1/2C ..guys can you help me in proving this one..tnx.. What have you been able to do with this so far? -Dan
Also must write the condition for this question we should have A + B + C = 180 degree. Then use the sum and product formula: sin P + sin Q = 2 sin ( P+Q)/2 cos ( P-Q)/2 etc.
Originally Posted by ibdutt Also must write the condition for this question we should have A + B + C = 180 degree. That's only if A, B, C are angles in a triangle. But it's a good question. @fireboy25: Are A, B, and C the angles of a triangle? -Dan
yes..the sum of A, B, C is 180..
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