Attachment 29289

I see this all the way to the point where Ca/Oa. I believe that is because OA and Oa are the same length. This is where I am lost is that PO multiplied by a or does he mean the angle POa. Can anyone shed some light on this for me?

Printable View

- September 24th 2013, 02:12 PMsepotoSpherical Trigonometry by Tod Hunter Article 14.
Attachment 29289

I see this all the way to the point where Ca/Oa. I believe that is because OA and Oa are the same length. This is where I am lost is that PO multiplied by a or does he mean the angle POa. Can anyone shed some light on this for me? - September 24th 2013, 05:44 PMchiroRe: Spherical Trigonometry by Tod Hunter Article 14.
Hey sepoto.

It refers to the angle POa itself. To understand this, use the ratio of opposite/hypotenuse which is Ca/Oa = sin(POa) (standard result). - September 24th 2013, 06:21 PMsepotoRe: Spherical Trigonometry by Tod Hunter Article 14.
Thank you. It makes much more sense to me now.