2(sin^-1x)cubed+5(sin^-1x)squared-1=0
Helppp solve the equation. Please?
As well as find the area and perimeter of the triangle.
cos(a) equals approximately -.125, b=8, c=8
Helpppp!
-Thanks
Let
Then we need to solve
The rational root theorem says that if there is a rational root for this polynomial equation it is of the form .
Trial and error shows that y = -1/2 is indeed a solution. This means we can draw out a factor of the form 2y + 1:
by any method of polynomial division you choose.
So finishing the solution I get that
So we need to solve for the three solutions:
and
and
The last two are impossible, as . So we only have
-Dan
To get the third side of the triangle, use the Law of Cosines. Then you can get the perimeter easily.
To get the area you can use Heron's formula.
-Dan