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Math Help - did i get this right?

  1. #1
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    did i get this right?

    my question is to write an expression that is quivalent to csc(2cot^-1(x)), that does not use trigonometric functions. I setup a triangle with the sides of 1, x, and the hypotenuse would be sqrt(1+x^2). after working through it i got: csc(2cot^1(x)) = (1 + x^2)/(2x)

    if anyone can let me know if that's right i would really appreciate it, if not i can put my work down to try to see where i went wrong. thanks
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  2. #2
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    Re: did i get this right?

    Hello, mikeythemaniac!

    \text{Write an expression that is equivalent to }\,\csc\left[2\cot^{\text{-}1}(x)\right].

    \text{I set up a triangle with the sides of }1, x\,\text{ and the hypotenuse would be }\sqrt{1+x^2}

    \text{After working through it, I got: }\csc\left[2\cot^{\text{-}1}(x)\right] \:=\: \frac{1 + x^2}{2x}

    Correct! . . . Good work!
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