Hello, mikeythemaniac!

Correct! . . . Good work!

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- Aug 21st 2013, 03:16 PM #1

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## did i get this right?

my question is to write an expression that is quivalent to csc(2cot^-1(x)), that does not use trigonometric functions. I setup a triangle with the sides of 1, x, and the hypotenuse would be sqrt(1+x^2). after working through it i got: csc(2cot^1(x)) = (1 + x^2)/(2x)

if anyone can let me know if that's right i would really appreciate it, if not i can put my work down to try to see where i went wrong. thanks

- Aug 21st 2013, 07:15 PM #2

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