my question is to write an expression that is quivalent to csc(2cot^-1(x)), that does not use trigonometric functions. I setup a triangle with the sides of 1, x, and the hypotenuse would be sqrt(1+x^2). after working through it i got: csc(2cot^1(x)) = (1 + x^2)/(2x)

if anyone can let me know if that's right i would really appreciate it, if not i can put my work down to try to see where i went wrong. thanks :)