Given:

SinA= -4/5

CosA= 3/5

CosA= radical8/3

CosB= -1/3

So the question is: cos(A-B) =cosA*cosB+sinA*sin(B)

(3/5)(-1/3)+(-4/5)(radical8/3)

-3/15+(-4radical8/15)=-3-4radical8/15

is this right!

Results 1 to 2 of 2

- July 21st 2013, 01:37 PM #1

- Joined
- Jun 2013
- From
- Toronto
- Posts
- 15

- July 21st 2013, 02:57 PM #2
## Re: Does this looks ok!

Aside from the SinB typo and needing parenthesis this is correct.

The correct answer is (-3 - 4radical8)/15.

Using LaTeX this is . (See our LaTeX Help Forum!)

You can also simplify a bit. What is in terms of ?

-Dan