Please Check my Problem did I do it right! (Must see)

So it ask to evaluate tan(A-B)

Given:

TanA: -4/3

TAnB: -√8 (negative radical8)

So far I got

Tan A = Tan A - Tan B / 1+ tan A Tan B

Tan A= -4/3-(-√8/1) divided 1+(-4/3)(-√8/1)

Tan A= __-4+3√8/3__ divided by __3+4√8/3__

So now I dived both -4+3√8/3 * 3/3+4√8

= **-4+3√3/3-4√8**

As my final answers(Evilgrin)

Re: Please Check my Problem did I do it right! (Must see)

Quote:

Originally Posted by

**TrimHonduras** So it ask to evaluate tan(A-B)

Given:

TanA: -4/3

TAnB: -√8 (negative radical8)

So far I got

Tan (A - B) = ( Tan A - Tan B ) / ( 1+ tan A Tan B )

Tan ( A - B )= [ -4/3-(-√8/1) ] / [ 1+(-4/3)(-√8/1) ]

Tan ( A - B )= [ __(-4+3√8)/3__ ] / [ __(3+4√8)/3__]

So now I dived both [(-4+3√8)/3] * [3/(3+4√8)]

= **(-4+3√3)/(3-4√8)**

As my final answers(Evilgrin)

Before I go any further, read where I have put in the necessary brackets, so that what you have written makes sense. Brackets are not optional and without them what you have written is garbage.

Re: Please Check my Problem did I do it right! (Must see)

thanks yours looks pretty neat... with brackets.. and yeah mines looks crappy.... hey thanks!