# supplementary exercise of trigo

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• Jun 28th 2013, 08:54 PM
Trefoil2727
supplementary exercise of trigo
If A, B, C are the angles of a triangle, prove that cos2A + cos2B + cos2 C = 1-2cosAcosBcosC

I've tried to use A+B+C=180, but I can't get the cos2 separately..
• Jun 28th 2013, 11:28 PM
mpx86
Re: supplementary exercise of trigo
this will help u
it is done for A+B=C
if A+B=C then prove that cos2A+cos2B + cos2C=1+2cosAcosB cos

it is ur task to do the same for a+b+c=180(method used will be identical)
• Jun 29th 2013, 06:27 AM
Trefoil2727
Re: supplementary exercise of trigo
Quote:

Originally Posted by mpx86
this will help u
it is done for A+B=C
if A+B=C then prove that cos2A+cos2B + cos2C=1+2cosAcosB cos

it is ur task to do the same for a+b+c=180(method used will be identical)

why cos2A+cos2B= 2cos(A+B)cos(A-B) ?
• Jun 29th 2013, 07:10 AM
mpx86
Re: supplementary exercise of trigo
½[sin ( Q+ β) + sin (Q − β)] = sin Q cos β,
so that
sin ( Q+ β) + sin ( Q− β) = 2 sin Q cos β. . . . . . (1)
Now put
Q + β = A
and
Q− β = B. . . . . . . . . . . . . . . .(2)
The left-hand side of line (1) then becomes
sin A + sin B.
This is now the left-hand side of (e), which is what we are trying to prove.
To complete the right−hand side of line (1), solve those simultaneous equations (2) for Q and β.
On adding them, 2Q = A + B,
so that
Q = ½(A + B).
On subtracting those two equations, 2β = A − B,
so that
β = ½(A − B).
On the right−hand side of line (1), substitute those expressions for and β. Line (1) then becomes
sin A + sin B = 2 sin ½(A + B) cos ½(A − B).

HERE A=2C AND B=2D
SUCH THAT sin 2C + sin 2D = 2 sin(C + D) cos (C − D).

IT IS YOUR TASK TO PROVE TH SAME FOR ADDITION OF 2 COSINES....