Prove the following identity:
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have you attempted anything yourself yet? I would recommended factoring it to start.
The identity $\displaystyle 1+tan^2A=sec^2A$ will also be useful
The given expression is 1-( Sec^{2}A-Tan^{2}A)^{2}=1-1^{2}=0
LHS = 1 - ( sec^4A - 2 sec^2 A tan^2 A + tan^4 A ) = 1 - ( sec ^2 A - tan ^2 A )^2 = 1 - 1 = 0 = RHS
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