# Trigonometry

• June 25th 2013, 05:20 AM
brosnan123
Trigonometry
• June 25th 2013, 05:43 AM
Re: Trigonometry
have you attempted anything yourself yet? I would recommended factoring it to start.
• June 25th 2013, 09:03 AM
Shakarri
Re: Trigonometry
The identity $1+tan^2A=sec^2A$ will also be useful
• June 25th 2013, 11:09 AM
sudhakar
Re: Trigonometry
The given expression is 1-( Sec2A-Tan2A)2=1-12=0
• June 27th 2013, 10:40 PM
ibdutt
Re: Trigonometry
LHS = 1 - ( sec^4A - 2 sec^2 A tan^2 A + tan^4 A )
= 1 - ( sec ^2 A - tan ^2 A )^2 = 1 - 1 = 0 = RHS