Prove the following identity:

http://image.tutorvista.com/contenti...ges/img893.gif

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- Jun 25th 2013, 04:20 AMbrosnan123Trigonometry
Prove the following identity:

http://image.tutorvista.com/contenti...ges/img893.gif - Jun 25th 2013, 04:43 AMadkinsjrRe: Trigonometry
have you attempted anything yourself yet? I would recommended factoring it to start.

- Jun 25th 2013, 08:03 AMShakarriRe: Trigonometry
The identity $\displaystyle 1+tan^2A=sec^2A$ will also be useful

- Jun 25th 2013, 10:09 AMsudhakarRe: Trigonometry
The given expression is 1-( Sec

^{2}A-Tan^{2}A)^{2}=1-1^{2}=0 - Jun 27th 2013, 09:40 PMibduttRe: Trigonometry
LHS = 1 - ( sec^4A - 2 sec^2 A tan^2 A + tan^4 A )

= 1 - ( sec ^2 A - tan ^2 A )^2 = 1 - 1 = 0 = RHS