will never work, as it is greater than 1.
Hi maths gurus.
I'm in need of some help here with the sine rule.
I have my sine rule values 3.1/sin20 = 5/sineB = 6/SineC
I am trying to find the value for the sine of B so what I did was 3.1/Sine(20)*5 to get 1.81 If I do the inverse sine it comes up with an error on my calculator so is this what I'm meant to do or what?
A little more clarification: you started from and divided both sides by 5 to get
. The right side is , NOT sin(B) so you cannot immediately take the arcsine. To solve for B, you have to take the reciprocal of both sides to get . then take the arcsine.