Here is a link to the tutorial on how to use LaTex (the math text):
LaTex Tutorial
I will look at your problem now.
4tan(x) = 6 [ 2tan(x)/1 - tan^{2}(x) ]
Let tan(x) = a
4a (1 - a^{2}) = 12a
1 - a^{2} = 12a/4a
1 - a^{2} = 3
therefore, a^{2} = -2
Which doesn't seem right?
Help would be appreciated, the solutions are 0, pi and 2pi
And how do people type in that math text??!
Thanks in advance
Here is a link to the tutorial on how to use LaTex (the math text):
LaTex Tutorial
I will look at your problem now.
Thanks for the reply and the tutorial. I got the solution, which was really simple. I feel quite silly.
0 = a^{3} + 2a
0 = a (a^{2} + 2)
therefore
tan x = 0 or tan^{2}x = -2
x = 0, π or 2π or no solution.
Can you help me with this one though:
cos(2x)cos([LaTeX ERROR: Convert failed] ) + sin(2x)sin([LaTeX ERROR: Convert failed] ) = [LaTeX ERROR: Convert failed] for [0, 2[LaTeX ERROR: Convert failed]
ANYWAY,
cos(2x)cos(π/3) + sin(2x)sin(π/3) = √3/2 for [0, 2π]
so
1/2 cos(2x) + √3/2 sin(2x) = √3/2
cos(2x) + √3 sin(2x) = √3
cos(2x) + 2√3[sin(x)cos(x)] = √3
And then I'm not sure, I tried many ways. Help would be appreciated xox