4tan(x) = 6 [ 2tan(x)/1 - tan^{2}(x) ]

Let tan(x) = a

4a (1 - a^{2}) = 12a

1 - a^{2}= 12a/4a

1 - a^{2}= 3

therefore, a^{2}= -2

Which doesn't seem right?

Help would be appreciated, the solutions are 0, pi and 2pi

And how do people type in that math text??!

Thanks in advance