Here is a link to the tutorial on how to use LaTex (the math text):
I will look at your problem now.
4tan(x) = 6 [ 2tan(x)/1 - tan2(x) ]
Let tan(x) = a
4a (1 - a2) = 12a
1 - a2 = 12a/4a
1 - a2 = 3
therefore, a2 = -2
Which doesn't seem right?
Help would be appreciated, the solutions are 0, pi and 2pi
And how do people type in that math text??!
Thanks in advance
Thanks for the reply and the tutorial. I got the solution, which was really simple. I feel quite silly.
0 = a3 + 2a
0 = a (a2 + 2)
tan x = 0 or tan2x = -2
x = 0, π or 2π or no solution.
Can you help me with this one though:
cos(2x)cos([LaTeX ERROR: Convert failed] ) + sin(2x)sin([LaTeX ERROR: Convert failed] ) = [LaTeX ERROR: Convert failed] for [0, 2[LaTeX ERROR: Convert failed]
cos(2x)cos(π/3) + sin(2x)sin(π/3) = √3/2 for [0, 2π]
1/2 cos(2x) + √3/2 sin(2x) = √3/2
cos(2x) + √3 sin(2x) = √3
cos(2x) + 2√3[sin(x)cos(x)] = √3
And then I'm not sure, I tried many ways. Help would be appreciated xox