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Finding trig function of given graph

So, one question i'm stuck in is "Find a formula for the graph of the function *y*=*f*(*x*) given in the figure above." (below)

Attachment 28358

For the formula f(t) = Acos(B(t+h))+C, I figured the following out:

amplitude = 3

period = 2π (2π/B=2π, B=1)

h (horizontal shift) = π

C (vertical shift) = 4

and replaced into the formula to get:

f(t) = 3cos(1(t+π))+4

Now when I graph that on my calculator, it looks fine, but it's not the correct answer. Where did I mess up? Am I even supposed to be using cos? The only reason I did is because it seemed like calculating h (the horizontal shift) would be easier for cos than sin, but I don't see why it shouldn't work either way.

Any help is greatly appreciated.

Re: Finding trig function of given graph

First of all, it should be obvious that your A value is negative. Why?

Re: Finding trig function of given graph

Quote:

Originally Posted by

**Prove It** First of all, it should be obvious that your A value is negative. Why?

I thought my A value was half the distance between by max and min Y values, so 7-1 = 6, 6/2 = +3 ? Unless i'm supposed to do it the other way round (-3)??

Or do you mean that rather than a shift, my graph is flipped around? So something like C**-**Acos(B(t+h)) ?

Re: Finding trig function of given graph

Yep. That was it. I plugged the values into C-Acos(B(t+h)) and I got 4-3cos(x), which was correct.

Thanks a ton for the help, I didn't even realize that my graph was a flipped cosine. However, for future reference, would it have also been right to see it as having shifted left/right by π like so: 4+3cos(x+/-π) ? In class, we were told to account for the difference that way, and it seems like that would be more universally applicable.