Hi!

What quadrant and location is the following angle?

$\displaystyle -\frac{11}{12}$

$\displaystyle -\frac{11}{12} = 2\pi -\frac{11\pi}{12}$

$\displaystyle \frac{13}{12} \implies$ Six and a half revolutions, stopping at $\displaystyle \pi$.

$\displaystyle \pi - \frac{\pi}{12} = \frac{11\pi}{12}$

Quadrant II.