Hello Everyone,
I can't figure out very well how to find the standard equation of the following ellipse.
I was trying the following steps.
Find squares (I'm not good at, finding squares)
Looking at the x part. If you want to get it into the form (ax+b)^{2} expanding it out might make it clearer. (ax+b)^{2}=a^{2}x^{2}+2abx+b^{2}
since the x^{2} part is 25x^{2} you know that a^{2}=25, a=5
The x part is -300. You know that 2ab=-300. and a=5 so b=-30
Lastly you need to balance the square by subtracting a constant.
For this to be true c must be equal to -900
Hello, vaironxxrd!
Before completing-the-square,
factor out the leading coefficients of the quadratic expressions.
Find the standard equation of the following ellipse:
. .
We have: . .
Factor:.
. . . . . .
. . . . . . . . . . . . . .
Divide by 1225:. . . . .