Hello Everyone,

I can't figure out very well how to find the standard equation of the following ellipse.

$\displaystyle 25x^2+49y^2-300x+49y-1251/4=0$

I was trying the following steps.

$\displaystyle [25x^2-300x +- ?]+ [ 49y^2+49y +- ? ]= 1251/4$ Find squares (I'm not good at, finding squares)