I have tried out the three equations. the value of h i got was 35 but on verification with third equation i got tan z = 1/16. Please verify the values.
Three points A, B and C are on a horizontal line such that AB = 70m and BC = 35m. The angles of elevation of the top of the tower are x, y and z, where tan x = 1/13, tan y = 1/15, and tan z = 1/20. The foot of the tower is at the same level as A, B and C. Find the height of the tower.
I can draw the diagram and have 3 equations in 2 unkowns, can't go any further. Please help
I agree with ibdutt: . must be
But then, we don't need point or angle
The tower is:
InCode:P * |** * | * * * | * * * h | * * * | * * * | * * * | x * y * z * Q * - - - * - - - * - - - - - - - * 13h A 70 B 35 C
You're both making the assumption that the base of the tower is on the same line as A, B and C.
That needn't be the case, and if it isn't it's perfectly possible to arrive at an answer consistent with the given values.
I have to go out now, but I can post a solution tomorrow unless either of you do so in the meanwhile.
Let the tower be of height h with base at D, (not on the line ABC), and top E.
so and similarly
We now have a triangle with with a point
Here are two different methods for finding the value of h.
(1) Using the cosine rule in the two triangles ABD and ACD.
Tidy up and equate the two and find that
(2) Using some co-ordinate geometry.
Arrange for the line ABC to be along the x-axis with A at the origin.
Take circles radii 13h, 15h and 20h at centres A, B and C respectively. The base of the tower D, will be at a common point of intersection.
The circles have equations
Expand the two brackets and subtract (1) from (2), (1) from (3) yielding (4) and (5),
Now multiply (4) by 3, (5) by 2 and subtract one from the other to get rid of x.
Tidy up and again find that
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