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Math Help - Trigonometry: bearing problems

  1. #1
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    Trigonometry: bearing problems

    I don't even know where to start with this problem...I know that i will end up drawing a triangle....but I could really use some assistance...I think that I did number 33 right, but i'm not quite sure

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  2. #2
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    Hello, aikenfan!

    (31) A ship leaves port at noon and has a bearing of S24W.
    The ship sails at 20 knots.
    How many nautical miles south and west will the ship have sailed by 6 pm?
    Code:
                    P
                    *
                   /|
                  / |
                 /  |
                /24|
               /    |
          120 /     |
             /      |
            /       |
           /        |
          * - - - - *
          A         S

    The ship leaves the port P at 12 noon and sails at 20 knots.
    . . In 6 hours, it has sailed 120 nautical miles to A.

    We have: . \cos24^o \:=\:\frac{PS}{120}\quad\Rightarrow\quad PS \:=\:120\!\cdot\!\cos24^o \:=\:109.6254549

    . . Therefore, the ship sailed about 109.6 nautical miles south.


    We have: . \sin24^o \:=\:\frac{AS}{120}\quad\Rightarrow\quad AS \:=\:120\!\cdot\!\sin24^o \:=\:48.80839717

    . . Therefore, the ship sailed about 48.8 nautical miles west.

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  3. #3
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    Thank you very much! I just have one more question...for number 32....how do i do this if it gives a time (rather than a distance)?
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  4. #4
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    Hello again, aikenfan!

    For number 32....how do i do this if it gives a time (rather than a distance)?

    Well, they did give you a distance . . . indirectly.

    The plane flew for 1.5 hours at 600 mph . . . That's 900 miles.

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