It is only multiples of 3, I was wondering if someone could please look over this? I am having an extremely hard time with these...i did not get #33...please help
Are you CERTAIN you have all the labels correct? It is rather confusing to use lower case on the drawing and upper case in the problem set.
1) ALWAYS remember that drawings may not be to scale. Do NOT let your eyes decieve you.
2) 30-60-90 ALWAYS has the long leg equal to $\displaystyle \sqrt{3}$ times the short leg.
Short = $\displaystyle 8$, Long = $\displaystyle 8\sqrt{3}$
Long = $\displaystyle 25$, Short = $\displaystyle \frac{25}{\sqrt{3}}$
Hello, aikenfan!
They're fine . . . except for #33 . . .$\displaystyle \begin{array}{cccc} & a & b & c \\Code:* * * c * 60° * * * a * 30° * * * * * * * * * b
33) & \_\_ & 25 & \_\_ \end{array} $
For this triangle $\displaystyle a:b:c$ is in the ratio: .$\displaystyle x:x\sqrt{3}:2x$
We are told: .$\displaystyle b = 25$
. . So we have: .$\displaystyle x\sqrt{3} \,=\,25\quad\Rightarrow\quad x \:=\:\frac{25}{\sqrt{3}} \:=\:\frac{25\sqrt{3}}{3} $
Therefore: .$\displaystyle \begin{array}{ccccc}a & = & x & = & \frac{25\sqrt{3}}{3} \\ c & = & 2x & = & \frac{50\sqrt{3}}{3}\end{array}$