Surely you understand that x + x = 2x...
As for the second, if you meant [tex]\displaystyle 5\left[ \sin{(x)} \right] ^2 [/tex], this is an equivalent way of writing so you would be correct. However, if you meant you would be wrong.
Hi guys, i have a couple question from my homework i am having trouble with a little more then a couple , if any one could help i would appreciate it.
1) Simplify or combine where possible, sin(x + x) = i get 2sinx (Answer is sin2x) why is the 2 there? not in front?
2) 5sinxsinx = i get 5sinx^2 (answer is 5sin^2x)
Thanks in advance.
Surely you understand that x + x = 2x...
As for the second, if you meant [tex]\displaystyle 5\left[ \sin{(x)} \right] ^2 [/tex], this is an equivalent way of writing so you would be correct. However, if you meant you would be wrong.
What? You think that sinx(sinx)= 1? For any a, a times a is designated " ". That's what that " " means. So in particular, and is just simpler notation. Strictly speaking "x" is an argument of the function "sin" so we should have parentheses. Perhaps if it were (sin(x))(sin(x)) it would be clearer that it should be sin^2(x), not " " which would be interpreted as " ".
After reading your comments i understand what i was not getting sometimes its the simple things that get me, One last follow up question if you math wizards don't mind,
Prove the following Cos(x-Pi)=Sin(x+3pi/2) : What i attempted to do was use the identity Sin(a+b)= sinAcosB+cosAsinB it came close but not what i needed, would any one be able to help?.
Thanks for all the help again i really do love this site, and sorry for my stupid questions .