# Equation Solution

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• Apr 1st 2013, 02:07 PM
ManosG
Equation Solution
Good afternoon. I want some help in this exercise:

Solve in R the equation $4x\sin(\omega x) - x^2 - 4 = 0$

I have tried to convert it in a perfect square form but i came out with this $(x - 2 \sin(\omega x))^2 + 4 (\cos(\omega x))^2 = 0$ and i can't solve this. Can anyone help, please?
• Apr 1st 2013, 02:16 PM
Ruun
Re: Equation Solution
If your perfect square is rigth you're almost done if $x$ is real. Because you have the sum of two squared quantities equal to zero, both shall be zero.

Wolframalpha says solve 4&#42;x&#42;sin&#40;w&#42;x&#41;-x&#94;2-4&#61;0 - Wolfram|Alpha
• Apr 1st 2013, 03:25 PM
ManosG
Re: Equation Solution
Thanks, but i am not permitted to solve it with Wolfram. I must use algebra-trigonometry of High School. That's why I have stucked at the sum of perfect squares.
• Apr 1st 2013, 05:15 PM
Prove It
Re: Equation Solution
Quote:

Originally Posted by ManosG
Good afternoon. I want some help in this exercise:

Solve in R the equation $4x\sin(\omega x) - x^2 - 4 = 0$

I have tried to convert it in a perfect square form but i came out with this $(x - 2 \sin(\omega x))^2 + 4 (\cos(\omega x))^2 = 0$ and i can't solve this. Can anyone help, please?

Where has this equation come from? I seriously doubt it could have come from high school, seeing as it's impossible to exactly solve equations that have the unknown both inside and outside of transcendental functions (unless you are very lucky and good at guessing).
• Apr 2nd 2013, 05:12 AM
ManosG
Re: Equation Solution
Ok, thanks very much!