1. x^{2/3}=4 //Really dont know T_T

2. 5^{x}=square root of 5

~ 5^{x}= 5 * 5^{1/2 }~ 5^{x}= 5^{3/2}//How did 3/2 happen? - .-

I dont know how to solve the ff fractional fractional exponents. please explain to me step by step. T_T

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- Mar 19th 2013, 10:43 PMKerkLuLogarithm: Fractional exponents
1. x

^{2/3}=4 //Really dont know T_T

2. 5^{x}=square root of 5

~ 5^{x}= 5 * 5^{1/2 }~ 5^{x}= 5^{3/2}//How did 3/2 happen? - .-

I dont know how to solve the ff fractional fractional exponents. please explain to me step by step. T_T - Mar 19th 2013, 11:01 PMProve ItRe: Logarithm: Fractional exponents
- Mar 19th 2013, 11:06 PMKerkLuRe: Logarithm: Fractional exponents
ohh sorry, my mistake xD That was still 5 square root of 5. Thanks :)

- Mar 19th 2013, 11:13 PMProve ItRe: Logarithm: Fractional exponents
It's because $\displaystyle \displaystyle \sqrt{5} = 5^{\frac{1}{2}}$, so $\displaystyle \displaystyle 5\sqrt{5} = 5^1 \cdot 5^{\frac{1}{2}} = 5^{1 + \frac{1}{2}} = 5^{\frac{3}{2}}$.

- Mar 19th 2013, 11:28 PMKerkLuRe: Logarithm: Fractional exponents
I forgot about that , tnx :) but how about no.1?

- Mar 20th 2013, 03:50 AMibduttRe: Logarithm: Fractional exponents
x^2/3 = 4

Both the sides should be raised to the power os 3/2

Thus we have [x^2/3]^3/2 = 4^3/2 that gives x = [4^1/2]^3=2^3= 8