I have the angle 2pi/3 and the radius of 6. What is the formula I'd use to calculate the exact coordinates?
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I think I figured it out, multiple the X,Y coordinates to by the radius. X = -1/2(6) Y = sqrt3/2(6) which gives me the coordinates (-3, 3sqrt3)
Originally Posted by wolfwood I think I figured it out, multiple the X,Y coordinates to by the radius. X = -1/2(6) Y = sqrt3/2(6) which gives me the coordinates (-3, 3sqrt3) Your point is $\displaystyle \left( {r\cos (\theta ),r\sin (\theta )} \right)$.
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