1. ## Finding Reference Angle

Hello again and again Everyone,

I'm having trouble finding a reference angle for the following angle.

$\displaystyle \theta = -1.8$

The book provides me with the answer which is $\displaystyle \theta' \approx 1.342$
But I cannot reach it, through my procedures.

I know the following is WRONG. But I'm trying to layout my method, to know where am I messing up.
I'm converting theta to be degrees, since it is easier for me.
-1.8 * 180 = -324
Angle coterminal to -324 = 36
Reference angle = 90 - 36
^- This is definitely wrong but I can't think of any other methods.

2. ## Re: Finding Reference Angle

Originally Posted by vaironxxrd
Hello again and again Everyone,

I'm having trouble finding a reference angle for the following angle.

$\displaystyle \theta = -1.8$

The book provides me with the answer which is $\displaystyle \theta' \approx 1.342$
But I cannot reach it, through my procedures.

I know the following is WRONG. But I'm trying to layout my method, to know where am I messing up.
I'm converting theta to be degrees, since it is easier for me.
-1.8 * 180 = -324
Angle coterminal to -324 = 36
Reference angle = 90 - 36
^- This is definitely wrong but I can't think of any other methods.
Your angle is in quadrant IV so the reference angle of +324 would be 360 - 324 = 36.

Also, did you remember to convert back to radians?

-Dan

3. ## Re: Finding Reference Angle

Originally Posted by vaironxxrd
Hello again and again Everyone,
I'm having trouble finding a reference angle for the following angle.
$\displaystyle \theta = -1.8$
The book provides me with the answer which is $\displaystyle \theta' \approx 1.342$
Take a look at this webpage.

Because $\displaystyle \frac{\pi}{2}<1.8<\pi$ the reference angle is $\displaystyle \pi-1.8$.

4. ## Re: Finding Reference Angle

Originally Posted by Plato
Take a look at this webpage.

Because $\displaystyle \frac{\pi}{2}<1.8<\pi$ the reference angle is $\displaystyle \pi-1.8$.
Really... Just forget about it ?

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