Here is a question, I've got an answer to it but I think its wrong

a) prove that (done)

http://latex.codecogs.com/gif.latex?...quiv tan\Theta

b) verify that

http://latex.codecogs.com/gif.latex?\Theta =180 is a solution to the equation

http://latex.codecogs.com/gif.latex?... 2-2cos2\Theta

Does this rearrange to, using part (a), http://latex.codecogs.com/gif.latex?2tan\Theta =0 so, http://latex.codecogs.com/gif.latex?2tan180 =0, which is correct??

c) Using your result in part (a), or otherwise, find the other two solutions, http://latex.codecogs.com/gif.latex?0< \Theta < 360, of the equation using http://latex.codecogs.com/gif.latex?... 2-2cos2\Theta

For this I said that this meant that http://latex.codecogs.com/gif.latex?tan\Theta =0 and the inverse tan of 0 = 0

So, using the general solution for tan, http://latex.codecogs.com/gif.latex?...= 180n + \beta and the fact that http://latex.codecogs.com/gif.latex?\beta = 0

I got the answers 0 and 360, but I'm doubtful as the range is http://latex.codecogs.com/gif.latex?0< \Theta < 360 with no 'greater/less than or equal to' in there??