Hey Garet.
Have you tried using a right angled triangle to get the simplification? (That is, one with a right angle and hypotenuse with the sine/cos/tan relationships?)
Hi,
I need help to derivate the following equation :
Arc tan (square(x-1)/x)
I can't get the correct answer which is : (2-x)/2(x^2+x-1) square (x-1)
Here is what I've done so far :
du/a^2+u^2
so :
du = 1/2square(x-1)
a^2 = x^2
u^2 = (x-1)
which give me :
1/2(x^2+x-1) square (x-1)
can't find where the 2 - x come from
thx for the help