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Math Help - Trigonometry question

  1. #1
    Newbie
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    Canada
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    Trigonometry question

    Hi,
    I need help to derivate the following equation :

    Arc tan (square(x-1)/x)

    I can't get the correct answer which is : (2-x)/2(x^2+x-1) square (x-1)

    Here is what I've done so far :

    du/a^2+u^2

    so :

    du = 1/2square(x-1)
    a^2 = x^2
    u^2 = (x-1)
    which give me :
    1/2(x^2+x-1) square (x-1)

    can't find where the 2 - x come from

    thx for the help
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  2. #2
    MHF Contributor
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    Re: Trigonometry question

    Hey Garet.

    Have you tried using a right angled triangle to get the simplification? (That is, one with a right angle and hypotenuse with the sine/cos/tan relationships?)
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  3. #3
    Super Member
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    Re: Trigonometry question

    Could you rewrite the question. The logic for the question is simple using function of a function rule.Trigonometry question-differentiation.png
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