Originally Posted by

**Furyan** Hello this question looked straight forward enough, but I'm stuck and would really appreciate some help.

Solve on the interval $\displaystyle 0\leq x \leq\2\pi$

$\displaystyle \cot\theta + 3\cot2\theta-1=0$

I tried writing it in terms of $\displaystyle \cos\theta$ and $\displaystyle \sin\theta$

And got this;

$\displaystyle \dfrac{5\cos^2\theat - 3\sin^2\theta}{2\sin\theta\cos\theta} =1 $, among various similar equations.

I have worked on from here a bit, but can't seem to get it in terms of a trigonometric equation I can then solve. I'd really appreciate it if somone would tell me if I'm on the right track and should keep going or if I need to approach the question in a different way.

Thank you very much.