Hello all. I have a problem : Proof that triangle has an 60^{0} angle if and only if $\displaystyle sin3\alpha+sin3\beta+sin3\gamma=0$ Please help, no idea
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Hey darence. First off, we know that all angles equal 180 degrees or pi radians. Now y = pi - b - pi/3 so prove that sin(3*pi/3) + sin(3*b) + sin(3*(2pi/3 - b) = 0 and you're done.
Give me explanation. I dont understand
Basically I set one angle to 60 degrees (or pi/3 radians) and the rest add up 180 degrees (or pi radians). Then you just show that the equation holds and then you're done.
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