Solve each equation for 0 < theta < 2(pie)
tan^2(theta) + 2tan(theta) - 5 = 0
I can't even remember how to do this...a little help? Please and thanks!
Hmm...I'm still not getting the answers it is giving:
0.97, 1.85, 4.11, 5.00 (in the textbook)
After doing calculations, the 2 roots are:
x = 0.449
x2 = 4.449
I convert both xs back into tan(theta).
tan(theta1) = 0.449
tan(theta2) = 4.449
Solve for both degree.
tan(theta1) = 24.2 degrees
tan(theta2) = 77.3 degrees
Convert both to radians.
theta1 = 0.422
theta 2 = 1.34
Which do not resemble the answers in the textbook. I'm lost.
we have $\displaystyle x = \tan \theta = \frac {-2 \pm \sqrt{2^2 - 4(1)(-5)}}2$
now simplify and solve for $\displaystyle \theta$ (remember to use referefernce angles to get all the angles in $\displaystyle 0 \le \theta \le 2 \pi$. as the answer tells you, you should have 4 angles not just two