Originally Posted by

**vaironxxrd** Hello again Everyone,

I had a question I was able to finally solve by myself but I was wondering if the following method is correct.

The problem is, $\displaystyle cot\theta = \frac{\sqrt{3}}{3}$

How I solved it...

$\displaystyle tan \theta = \frac{1}{cot \theta}$

$\displaystyle tan \theta = \frac{1}{\frac{\sqrt3}{3}}$ Which equals 1.732

Since I knew the question asked about special triangles I did the following

tan(30°) = 0.57735

tan(45°) = 1

tan(60°) = 1.73205

Therefore $\displaystyle \theta$ = 60°

Is this an acceptable method or the "right" method?