# ***************can someone help me work this out please *****************

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• Jan 20th 2013, 12:20 PM
gary147
***************can someone help me work this out please *****************
Ive uploaded a triangle .. i need the length of a??

i can gt 8000 divide sin39 = a divide sin112

i just dont no how to get the length can someone please have look and help me do it

thanks
• Jan 20th 2013, 01:03 PM
Barioth
Re: ***************can someone help me work this out please *****************
Hey mate, I took a quick look at your triangle.

I know ther eis some formula for these thing. But if you're like me, you probably don't know it and don't wana learn it.

So I'll tell you how I had do it.

I would split the upper angle (in this case B) and make a line from it to the botom of the triangle. This way I would have 2 right angled triangle.

With right angled triangle everything should be easier! With sin/cos and tan you should be able to work it ou!
• Jan 20th 2013, 05:57 PM
gary147
Re: ***************can someone help me work this out please *****************
i did the line down the middle to create to 90 degree angles.. got the length to be 11.78647776 sound right????????
• Jan 20th 2013, 06:02 PM
Barioth
Re: ***************can someone help me work this out please *****************
Sound good to me!
• Jan 20th 2013, 06:06 PM
gary147
Re: ***************can someone help me work this out please *****************
wow ive learnt it hhaha
• Jan 20th 2013, 06:13 PM
gary147
Re: ***************can someone help me work this out please *****************
any idea how to find the co-ordinates for the front left corner of the building? the top left angle of the triangle??

can you explain how to find it please
• Jan 20th 2013, 06:37 PM
Deveno
Re: ***************can someone help me work this out please *****************
we need one more angle or length to find that. as it is, we have one side, and one angle. that only gives us two points of the triangle that we can definitely locate (the front right corner of the building, and the reference point).
• Jan 20th 2013, 06:39 PM
gary147
Re: ***************can someone help me work this out please *****************
thats defo all the information i got and should be able to get the co-ords... hard i know :( well stuck lol
• Jan 20th 2013, 06:43 PM
gary147
Re: ***************can someone help me work this out please *****************
the length of the left side of triangle is 11.78647783 Metres and top left angle is 38 degrees
• Jan 20th 2013, 06:43 PM
Barioth
Re: ***************can someone help me work this out please *****************
Sadly I think Deveno is right. I can't think of any way to find something out of this. :(
• Jan 20th 2013, 06:44 PM
gary147
Re: ***************can someone help me work this out please *****************
does the info i just said help m8?
• Jan 20th 2013, 06:45 PM
gary147
Re: ***************can someone help me work this out please *****************
angle is 39 degrees sorry
• Jan 20th 2013, 06:47 PM
Barioth
Re: ***************can someone help me work this out please *****************
"If you know any 3 of the sides or angles ...

... you can find the other 3

(Except for 3 angles, because you need at least
one side to find how big the triangle is.)"

With these info we could work it out, like we did with the first one, making two right angled triangle.
with just one angle and one lenght, you can't do nothing (Unless its a right angled triangle.)
• Jan 20th 2013, 06:48 PM
Deveno
Re: ***************can someone help me work this out please *****************
that doesn't sound right if the given side is 5m, can you confirm that is the proper length (the pdf is blurry)?
• Jan 20th 2013, 06:50 PM
Barioth
Re: ***************can someone help me work this out please *****************
How could you find out these value?

I wouldn't trust them. The only way to know them is if the plan is scaling and you took the measure with your instrument. Wich is probably not the way to solve this
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