tan(A/2) + cot(A/2) = 2cosecA

Hello

Could someone please help me start with proving the following identity:

I'm trying to show that the L.H.S = the R.H.S. I've tried finding the half angle formula for , but it looks like a quadratic. I have also tried writing the L.H.S as a single term. I'm totally stuck. A hint would be greatly appreciated.

Thank you

Re: tan(A/2) + cot9A/2) = 2cosecA

Quote:

Originally Posted by

**Furyan** Hello

Could someone please help me start with proving the following identity:

To save notation let .

Re: tan(A/2) + cot9A/2) = 2cosecA

Hello Plato,

Thank you so much. I clearly wasn't trying hard enough to write the L.H.S as a single term. I totally missed that.

Thank you for all your help and patience, it's very much appreciated.

Re: tan(A/2) + cot9A/2) = 2cosecA

...and I actually understand the use of the double angle formula to equate the following.

Edit: Understand might be an over statement, but I get it.