You want to find within your given boundaries where and , AS LONG AS .
Edit: To answer your apparent question, you are right, is NOT a solution, because , which cannot be in a denominator.
Hey everyone!
Sinxtanx - tanx = 0 ; Solve for x? 0 < x < 2pi (and including 0 and 2pi, not sure how to input that)
This is what I have done so far--
sinxtanx - tanx = 0
tanx (sinx - 1) = 0
Set tanx = 0 and sinx - 1 = 0
tanx = 0 when x = 0, pi, 2pi
sinx - 1 = 0
sinx = 1
x = pi/2
so x = 0, pi/2, pi, 2pi
What I am not sure about, is if pi/2 is a solution or not, as I am thinking that tanx is undefined at pi/2.
You want to find within your given boundaries where and , AS LONG AS .
Edit: To answer your apparent question, you are right, is NOT a solution, because , which cannot be in a denominator.