1. Show that OM = 6 cos θ - 2 sin θ

2. Show that area of triangle OAM is 10 sin 2(θ + α)

[OM = R cos (θ + α)]

[AM = R sin (θ + α)]

3. Given that θ can vary, find the maximum value of the area of triangle OAM.

Refer to: http://i49.tinypic.com/1pueqq.png

ABO & BNO = right angled triangles

OB = 6 cm

AB = 2 cm

line AM perpendicular to ON