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Math Help - Right triangles: help, please

  1. #1
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    Right triangles: help, please

    There are only eight problems...I think that I have the first two down...and possibly the last two..not sure if they are correct, if maybe someone can check my work so that I know if I am doing them correctly...The others, I don't really understand where to start...if maybe someone could help me...
    The directions for 9 -11 got cut off a bit...should say determine the third side and then find the other five trig functions
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by aikenfan View Post
    There are only eight problems...I think that I have the first two down...and possibly the last two..not sure if they are correct, if maybe someone can check my work so that I know if I am doing them correctly...The others, I don't really understand where to start...if maybe someone could help me...
    The directions for 9 -11 got cut off a bit...should say determine the third side and then find the other five trig functions
    In 4, you can simplify the \sqrt{468}.

    For 39:
    \frac{sin(\theta)}{cos(\theta)} + \frac{cos(\theta)}{sin(\theta)} = csc(\theta)sec(\theta)

    Just add the fractions:
    \frac{sin^2(\theta) + cos^2(\theta)}{sin(\theta)cos(\theta)} = csc(\theta)sec(\theta)

    In 46 is the argument in radians? That's the only way I can replicate your answer.

    The rest look good!

    -Dan
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  3. #3
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    Hello,

    for #11:

    \sec(\theta)=4~\implies~\frac1{\cos(\theta)}=4 ~\implies~\cos(\theta)=\frac14

    for #33: change only the \cot(\theta):

    \tan(\theta) \cdot \frac1{\tan(\theta)}=1
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