Re: Trigonometric Equations

Re: Trigonometric Equations

Just do little bit calculations and proceed

3 = 2 sin x tanx = 2 sinx ( sinx / cos x ) = 2 sin^2 x / cosx

So we get 3cosx = 2 sin^2 x

Now convert sin2x in terms of cos^2 x and you have a quadratic in cos x.

I am sure you can now solve it further.

Re: Trigonometric Equations

Ok I see what everyone is getting at now, I will put what I have below but I need to work out the equation from 0 to 2pi. I have the first one worked out not sure how to get the second:

Now I know there is another but I am usure how to find it ?

Re: Trigonometric Equations

If you are working up to then there will be another angle in the circle that gives . Your calculator will only give you the one from 0 to

Re: Trigonometric Equations

I can see graphically that I can find the next angle by simply doing 2pi - 1.04 , Is this is the corret way to do it ?

Re: Trigonometric Equations

Yes, that sounds good to me.

Re: Trigonometric Equations