# Trigonometric functions

• Dec 31st 2012, 11:29 AM
xoxo
Trigonometric functions
The function y=sin(x-p)+d has a vertical translation of -3 and passes through the point (pi/6, -2). Determine the values of p and d

My attempt
d= -3
-2= sin (pi/6 - p) -3
1 = 1/2 - sinp
1-1/2= - sinp
1/2= - sinp
-1/2= sinp

The question didn't specify a domain so how would I find the value of p?
• Dec 31st 2012, 11:37 AM
skeeter
Re: Trigonometric functions
Quote:

Originally Posted by xoxo
The function y=sin(x-p)+d has a vertical translation of -3 and passes through the point (pi/6, -2). Determine the values of p and d

My attempt
d= -3
-2= sin (pi/6 - p) -3
1 = 1/2 - sinp

note ...

${\color{red}\sin\left(\frac{\pi}{6} - p\right) \ne \sin\left(\frac{\pi}{6}\right) - \sin{p}}$
• Jan 1st 2013, 12:21 AM
ibdutt
Re: Trigonometric functions
-2 = sin ( π/6-p)-3
Or
sin ( π/6-p)=1=sin⁡ π/2
Therefore one of the solution would be
π/6-p = π/2 That gives p = - π/3