Re: Trigonometric functions

Quote:

Originally Posted by

**xoxo** The function y=sin(x-p)+d has a vertical translation of -3 and passes through the point (pi/6, -2). Determine the values of p and d

My attempt

d= -3

-2= sin (pi/6 - p) -3

1 = 1/2 - sinp

note ...

$\displaystyle {\color{red}\sin\left(\frac{\pi}{6} - p\right) \ne \sin\left(\frac{\pi}{6}\right) - \sin{p}}$

Re: Trigonometric functions

-2 = sin ( π/6-p)-3

Or

sin ( π/6-p)=1=sin π/2

Therefore one of the solution would be

π/6-p = π/2 That gives p = - π/3