solve the following for 0 <_ θ <_ 4pi
The <_ represents less than or equal to.
Sin[θ]^2 == -Cos[θ]
Would like a step by step process for approaching this question. Thanks.
If the question is to solve $\displaystyle \sin^2(\theta)=-\cos(\theta)$ then that is equivalent to solving $\displaystyle \cos^2(\theta)-\cos(\theta)-1=0$.
Or $\displaystyle u^2-u-1=0$ where $\displaystyle u=\cos(\theta).$
If that is not what it means, then please correct it.
Very unhelpful, you fail to communicate what requires solving and instead would rather confuse those seeking assistance. This is not a tutoring service obviously but its suppose to be a "math help" forum so it totally defeats the purpose if you are unwilling to help solve the problem at hand. Why would you ask me to solve a question totally unrelated if I do not know how it connects to the end answer? That is not going to help anyone. Geez very disappointing..
Do you know how to solve cos(θ) = k?
Do you know the identity sin^2(θ) + cos^2(θ) == 1?
Can you solve quadratic equations?
These are prerequisites to solving this equation.