solve the following for 0 <_ θ <_ 4pi

The <_ represents less than or equal to.

Sin[θ]^2 == -Cos[θ]

Would like a step by step process for approaching this question. Thanks.

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- Dec 27th 2012, 11:50 AMdcpc10Trig Identities - solve the following for 0 <_ θ <_ 4pi
solve the following for 0 <_ θ <_ 4pi

The <_ represents less than or equal to.

Sin[θ]^2 == -Cos[θ]

Would like a step by step process for approaching this question. Thanks. - Dec 27th 2012, 11:58 AMPlatoRe: Trig Identities - solve the following for 0 <_ θ <_ 4pi
- Dec 27th 2012, 12:10 PMdcpc10Re: Trig Identities - solve the following for 0 <_ θ <_ 4pi
Yes that is what it means.

- Dec 27th 2012, 12:29 PMHallsofIvyRe: Trig Identities - solve the following for 0 <_ θ <_ 4pi
So you can solve it now?

- Dec 27th 2012, 01:17 PMdcpc10Re: Trig Identities - solve the following for 0 <_ θ <_ 4pi
No because I would appreciate a step by step process to solve it. That was the reasoning for making the thread in the first place. This is for gr 12 advanced functions.

- Dec 27th 2012, 01:23 PMPlatoRe: Trig Identities - solve the following for 0 <_ θ <_ 4pi
- Dec 27th 2012, 01:37 PMdcpc10Re: Trig Identities - solve the following for 0 <_ θ <_ 4pi
Please help me with that.

- Dec 27th 2012, 01:41 PMPlatoRe: Trig Identities - solve the following for 0 <_ θ <_ 4pi
- Dec 27th 2012, 02:09 PMdcpc10Re: Trig Identities - solve the following for 0 <_ θ <_ 4pi
Very unhelpful, you fail to communicate what requires solving and instead would rather confuse those seeking assistance. This is not a tutoring service obviously but its suppose to be a "math help" forum so it totally defeats the purpose if you are unwilling to help solve the problem at hand. Why would you ask me to solve a question totally unrelated if I do not know how it connects to the end answer? That is not going to help anyone. Geez very disappointing..

- Dec 28th 2012, 10:38 AMkinhew93Re: Trig Identities - solve the following for 0 <_ θ <_ 4pi
Do you know how to solve cos(θ) = k?

Do you know the identity sin^2(θ) + cos^2(θ) == 1?

Can you solve quadratic equations?

These are prerequisites to solving this equation.