# Math Help - Solving for X with sin²

1. ## Solving for X with sin²

So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:

sin²X=0.25

Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

All help appreciated

2. ## Re: Solving for X with sin²

Originally Posted by acwilson96
So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:
sin²X=0.25
Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

Surely you realize that $\sin(x)=\pm 0.5~?$

3. ## Re: Solving for X with sin²

No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?

4. ## Re: Solving for X with sin²

Originally Posted by acwilson96
No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?
If $u^2=0.25$ then $u=\pm 0.5~.$

5. ## Re: Solving for X with sin²

oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25

6. ## Re: Solving for X with sin²

Originally Posted by acwilson96
oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25

Well $\sin^2(x)=[\sin(x)]^2$.

Is the question really $\sin(\sqrt{x})=0.25~?$.

Which is it?

7. ## Re: Solving for X with sin²

Ok i guess its just a rule you need to know that sin²x=(sinx)²
Il keep that in mind. So the answer would inverse sin of 1/2

8. ## Re: Solving for X with sin²

Originally Posted by acwilson96
Ok i guess its just a rule you need to know that sin²x=(sinx)²
Il keep that in mind. So the answer would inverse sin of 1/2

$x=\pm\arcsin(0.5)$