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Math Help - Solving for X with sin²

  1. #1
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    Solving for X with sin²

    So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:

    sin²X=0.25

    Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

    All help appreciated
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  2. #2
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    Re: Solving for X with sin²

    Quote Originally Posted by acwilson96 View Post
    So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:
    sin²X=0.25
    Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

    Surely you realize that \sin(x)=\pm 0.5~?
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  3. #3
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    Re: Solving for X with sin²

    No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?
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    Re: Solving for X with sin²

    Quote Originally Posted by acwilson96 View Post
    No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?
    If u^2=0.25 then u=\pm 0.5~.
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    Re: Solving for X with sin²

    oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25
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    Re: Solving for X with sin²

    Quote Originally Posted by acwilson96 View Post
    oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25

    Well \sin^2(x)=[\sin(x)]^2.

    Is the question really \sin(\sqrt{x})=0.25~?.

    Which is it?
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  7. #7
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    Re: Solving for X with sin²

    Ok i guess its just a rule you need to know that sin²x=(sinx)²
    Il keep that in mind. So the answer would inverse sin of 1/2
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    Re: Solving for X with sin²

    Quote Originally Posted by acwilson96 View Post
    Ok i guess its just a rule you need to know that sin²x=(sinx)²
    Il keep that in mind. So the answer would inverse sin of 1/2

    x=\pm\arcsin(0.5)
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