Solving for X with sin²

So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:

sin²X=0.25

Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

All help appreciated

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Originally Posted by acwilson96

So I missed a week of school and the holidays started and to catch up I have been given some work and I was struggling to complete this as I haven't had any tuition on how to:
sin²X=0.25
Its been bugging me and I don't know what to do to get rid of the sin². Had it just been sin I would have 'inverse sined' a quarter

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Surely you realize that

No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?

Quote:

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Originally Posted by acwilson96

No sorry i didnt, im doing higher maths(SQA) and im not sure that is in the syllabus or perhaps i just missed it. But what steps do I do to get rid of sin²?

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If then

oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25

Quote:

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Originally Posted by acwilson96

oh right yes, i understand that but i thought if you square root then it would be sin(root x )= 0.25

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Well .

Is the question really .

Which is it?

Ok i guess its just a rule you need to know that sin²x=(sinx)²
Il keep that in mind. So the answer would inverse sin of 1/2

Quote:

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Originally Posted by acwilson96

Ok i guess its just a rule you need to know that sin²x=(sinx)²
Il keep that in mind. So the answer would inverse sin of 1/2

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