r=a sin(x)

r=a cos(2x)

How would I solve the following equation I know cos(2x)=2cos^2-1,1-sin^2(x)

But I am not sure where to begin.

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- December 15th 2012, 11:26 AMhomeylova223How to solve the following trig equation
r=a sin(x)

r=a cos(2x)

How would I solve the following equation I know cos(2x)=2cos^2-1,1-sin^2(x)

But I am not sure where to begin. - December 15th 2012, 11:55 AMjakncokeRe: How to solve the following trig equation
Set them equal to each other , the a's cancel, so you get .

Now, , so , so you got , so . You can see that at , so .

So your solution set would be where K is an integer. - December 15th 2012, 11:57 AMskeeterRe: How to solve the following trig equation

can you finish? - December 15th 2012, 03:36 PMProve ItRe: How to solve the following trig equation
Let's not forget, you can NOT divide by 0. What should have been done is...

and then follow the abovementioned methods... - December 15th 2012, 06:40 PMhomeylova223Re: How to solve the following trig equation
thanks for your responses. They have been most helpful.