The equation is a logarithm problem that reads:
(a^2)(e^-ax)-(b^2)(e^-bx)=0 where a>b
The answer is:
(2(log[base e]a-log[base e]b))/(a-b)
How do I get from the problem to the solution.
Thank you
Hello, Crisor2431!
I assume that you know that is written
(a^2)(e^-ax)-(b^2)(e^-bx)=0 where a>b
The answer is: (2(log[base e]a - log[base e]b)) / (a - b)
How do I get from the problem to the solution?
We have: .
. . . . . . . .
Therefore: .