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Math Help - [help] Can't figure out how to complete a parabolic equation

  1. #1
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    Angry [help] Can't figure out how to complete a parabolic equation

    Hey everyone!

    I recently did a rocket project and I have the following things calculated (attached), however I'm supposed to get my data in the format:

    y - k = a(x - h)^2

    I figured out the height on my own by using tangent, but I'm not sure how to get it in the correct format.

    Thanks for help in advance!
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  2. #2
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    Re: [help] Can't figure out how to complete a parabolic equation

    you have t = 6 seconds ... you need \Delta x to get the parabola as a function of x
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    Re: [help] Can't figure out how to complete a parabolic equation

    Could I somehow use points to figure that out? Since the vertex would be (3,33.12) and another point I could use would be the origin at (0,0)?
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    Re: [help] Can't figure out how to complete a parabolic equation

    the vertex is not x = 3 , it is t = 3 ...

    are you wanting the parabola as height vs. displacement or height vs. time?
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  5. #5
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    Re: [help] Can't figure out how to complete a parabolic equation

    I asked my professor, and he just wants the flight path (which I'm guessing just the equation?)

    This is what I have but I feel like something is way off when it comes down to the equation..
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    Re: [help] Can't figure out how to complete a parabolic equation

    how far horizontally did the rocket land from where it was launched?
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    Re: [help] Can't figure out how to complete a parabolic equation

    Another thing you can do is write your parabola in the general form h= ax^2+ bx+ c. You know that when x= 0, h= 0 so 0= a(0)^2+ b(0)+ c= c, that when x= 91, h= 0 so that 0= a(91)^2+ b(91)+ c, and that when x= 91/2= 45.5, h= 33.12 so that 33.12= a(45.5)^2+ b(45.5)+ c (a parabola is symmetric so we know the vertex is half way between 0 and 91 feet). That gives three linear equations to solve for a, b, and c.
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