Show me the steps to solving complex numbers involving e?

**INeedOfHelp** · December 4th 2012, 04:15 PM

My teacher didn't go into too much detail on these equations and they were on a test, so I'd like to know how to solve these equations for my final.

Z=

Show me the steps to solving complex numbers involving e?-codecogseqn-1-.gif

Can someone show me the steps how to get this complex number into algebraic form answer Z=4i ?

Find the product of

Show me the steps to solving complex numbers involving e?-codecogseqn-2-.gif

and conjugate Z?

How do I solve to get the answer 27?

**Soroban** · December 4th 2012, 05:02 PM

Hello, INeedOfHelp!

$z \,=\,4e^{\frac{\pi}{2}i}$

Can someone show me the steps how to get this complex number into algebraic form: $z 4i$

$z \:=\:4e^{\frac{\pi}{2}i} \;=\;4\left(\cos\tfrac{\pi}{2} + i\sin\tfrac{\pi}{2}\right) \;=\; 4(0 + i\!\cdot\!1) \;=\;4i$

Find the product of $z \,=\,3\;\!\sqrt{3}e^{\pi i}$ and its conjugate $\overline{z}$

How do I solve to get the answer $27$ ?

We have: . $\begin{Bmatrix}z &=& 3\sqrt{3}\;\!e^{\pi i} \\ \\[-3mm] \overline{z} &=& 3\sqrt{3}\;\!e^{-\pi i} \end{Bmatrix}$

Therefore: . $z\cdot\overline{z} \;=\;\left(3\sqrt{3}\;\!e^{\pi i}\right)\left(3\sqrt{3}\;\!e^{-\pi i}\right) \;=\; \left(3\sqrt{3}\cdot3\sqrt{3}\right)\left(e^{\pi i}\cdot e^{-\pi i}\right)$

n . . . . . . . . . . . $=\;(27)(e^0) \;=\;(27)(1) \;=\;27$

**INeedOfHelp** · December 5th 2012, 10:33 AM

Oh well that's easy enough, thank you very much.

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