
trig identities
Hello, I am trying to prove this identity: (cscxcotx)^2=(1cosx)/(1+cosx)
currently I am did these steps:
(csc(x)  cot(x)) (csc(x)  cot(x)) = (cscxcotx)^2=(1cosx)/(1+cosx)
csc^2(x)  2cot(x)csc(x) + cot^2(x) = (cscxcotx)^2=(1cosx)/(1+cosx)
(1/sin^2(x))  2(cos(x)/sin(x))(1/sin(x)) + (cos^2(x) / sin^2(x)) = (cscxcotx)^2=(1cosx)/(1+cosx)
(1  2cos(x) + cos^2(x)) / sin^2(x) = (cscxcotx)^2=(1cosx)/(1+cosx)
Now I am stuck :S
please help and thanks!

Re: trig identities

Re: trig identities
Quote:
Originally Posted by
Prove It
umm, is it not possible to continue from what I am doing?
btw, how did you know you had to multiply by (1cosx)?
like I would never have thought of that!