cosθ= 24/25

The angle lies in quadrant 1; 0<θ<90

Find sin2θ

I know you would use either the formula cos^2θ- sin^2θor 2sinθcosθ

And I know that the answer is 339/625, but I do not know how to get that answer?

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- Nov 27th 2012, 03:46 PMwhittwhittHelp with Double Angle Identities!!!
cos

**θ**= 24/25

The angle lies in quadrant 1; 0<**θ**<90

Find sin2**θ**

I know you would use either the formula cos^2**θ**- sin^2**θ**or 2sin**θ**cos**θ**

And I know that the answer is 339/625, but I do not know how to get that answer? - Nov 27th 2012, 04:39 PMtopsquarkRe: Help with Double Angle Identities!!!
- Nov 27th 2012, 04:39 PMHallsofIvyRe: Help with Double Angle Identities!!!
Yes, you use one of those but which? One is and which is ? (What happens if ?)

If and is in the first quadrant what is ? (You**do**know that , don't you? - Nov 27th 2012, 04:41 PMzhandeleRe: Help with Double Angle Identities!!!
Let me see ... is your difficulty that you work the problem out, but you get an answer different from 339/625?

If so, maybe you answer is right. I also get something different from 339/625.

Could you show us what you did to find your answer.? - Nov 27th 2012, 04:52 PMwhittwhittRe: Help with Double Angle Identities!!!
My teacher gave us the answers so that we could check to see if we were doing the problem right.

- Nov 27th 2012, 04:57 PMzhandeleRe: Help with Double Angle Identities!!!
Well, he might've made a typo or something. What answer do you get?

- Nov 27th 2012, 05:08 PMwhittwhittRe: Help with Double Angle Identities!!!
Could you guys help me with one more problem? ... I promise I wrote this one down correctly

Thank you!

Could you help me with another problem?

secθ = -(sqrt41)/4

In quadrant 3; cosθ > 0

Find sin2θ - Nov 27th 2012, 05:13 PMzhandeleRe: Help with Double Angle Identities!!!
This is the same kind of problem as the last one. Only you say cos(theta) > 0? In quadrant III, cos < 0, or so I believe. Am I wrong? Do you mean that cos(2 theta) > 0?

Oh, I see. You mean that sin(theta) < 0. In quadrant 3 both functions > 0. That means theta > pi, so 2*theta > 2pi, the answer is probably in quadrant 1. You'd expect the sin(2 theta) to be > 0, right? - Nov 27th 2012, 05:49 PMzhandeleRe: Help with Double Angle Identities!!!
I have to go to sleep now, but do you know the first step to take? I'll give you a hint if not.