Hi,

Doing a tension in cable problem, Trying to find T, ended up with this, can this be arranged to find that? If so, an explanation would be very helpful

0.25(T*sin21) + 4.88(T*cos21) = 50510.8

Thanks

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- Nov 27th 2012, 08:40 AMMMCSRe-arranging Trig equation
Hi,

Doing a tension in cable problem, Trying to find T, ended up with this, can this be arranged to find that? If so, an explanation would be very helpful

0.25(T*sin21) + 4.88(T*cos21) = 50510.8

Thanks - Nov 27th 2012, 08:57 AMebainesRe: Re-arranging Trig equation
You have:

$\displaystyle 0.25T \sin \theta + 4.88 T \cos \theta = 50510.8 $

where $\displaystyle \theta$ = 21 degrees. This is the same as:

$\displaystyle T(0.25 \sin \theta + 4.88 \cos \theta) = 50510.8 $

Rearrange to get:

$\displaystyle T= \frac {50510.8}{0.25 \sin \theta + 4.88 \cos \theta}$ - Nov 27th 2012, 09:05 AMMMCSRe: Re-arranging Trig equation
Seems so simple when written like that. i was expecting something more complicated.

Thanks very much