is a unit circle value ... ,
has two solutions, one in quad II and one in quad III
gives the solution in quad II
gives the quad III solution
btw, this is pi ...
and this is pie ...
Ok, I can't figure out how to do this. I understand that you treat this like X^(2)+ X+1 and I can get to the point where you find what cos is equil to, but when puting the unit circle vallues is where im confused. Ok I have recently swiched to schools because I just had surgery so I couldnt be around that many people at a time. My other teacher told us we could not have decimal answers in this unit and in this new book I got there is decimal answers in it. I have no idea how to get the decimal answers. So here is the question Im trying to figure out.
Solve the equation algibraically over the domain 0<X<2pie: sec^(2)X + 5secX+ 6=0
This is my work, please tell me if im doing anything wrong
(sec+3)(sec+2)=0
secX=-3 secX=-2
1/(cos -3) 1/(cos -2)
cos= -1/3 cos=-1/2
2pie/3, 4pie/3...
So, now how do I get the decimal answers?
The book say the answers are 4pie/3, 2pie/3, 4.37, 1.91