Ok, I'm supposed to find sin$\displaystyle \theta$ when cos$\displaystyle \theta$ = $\displaystyle \frac{1}{3}$. The answer is $\displaystyle \frac{2\sqrt{2}}{3}$. I got $\displaystyle \sqrt{\frac{8}{9}$. Does this somehow simplify to the correct answer? it seems like it might, but my algebra skills are terrible.